Question

if x²+1/x²=18 then find the value of x-1/x​

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

$\frac{(x^{2} + 1)}{x^{2} } = 18$

x² + 1 = 18x²

17x² = 1

$x^{2} = \frac{1}{17}$

$x = \sqrt{\frac{1}{17}}$

$\frac{(x - 1)}{x }$

$\frac{(\sqrt{\frac{1}{17} } - 1)}{\sqrt{\frac{1}{17} } }$

$\frac{(\sqrt{\frac{1}{17} } - 1)}{\sqrt{\frac{1}{17} } }* \frac{\sqrt{\frac{1}{17} } }{\sqrt{\frac{1}{17} } }$

$\frac{( \frac{1}{17}-\sqrt{\frac{1}{17} } )}{{\frac{1}{17} } }$

$\ 17*{( \frac{1}{17}-\sqrt{\frac{1}{17} } )}} }$

$\ 1- 17\sqrt{\frac{1}{17}$

$\ 1- \sqrt{17}$