Question

if x²+1÷x²=27,find the value of x+1÷x​

Answer 1

Answer:

1+root26

Step-by-step explanation:

x^2+1/x^2=27

x^2+1=27x^2

26x^2=1

x=1/root26

next see in pic

Answer 2

Answer:

$1+\sqrt{26}$

Step-by-step explanation:

solve for x in first equation:

$\frac{x^{2}+1}{x^{2}}=27\\x^{2}+1=27x^{2}\\1=26x^{2}\\\frac{1}{26}=x^{2}\\\sqrt{\frac{1}{26}}=x$

plug x into the second equation:

$\frac{x+1}{x}\\\frac{\sqrt{\frac{1}{26}}+1}{\sqrt{\frac{1}{26}}}\\\frac{\sqrt{\frac{1}{26}}}{\sqrt{\frac{1}{26}}}+\frac{1}{\sqrt{\frac{1}{26}}}\\1+\frac{1}{\sqrt{\frac{1}{26}}}\\1+\sqrt{26}$

so our answer is:

$1+\sqrt{26}$