If x2 + 1/x2 = 27 ,find the values of each of the following:
i) x + 1/x ii) x- 1/x
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Given:
- x² + 1/x² = 27
We know that
- x² + 1/x² = (x+1/x)² - 2·x·1/x [ a² + b² = (a+b)² - 2 ab ]
⇒ 27 = (x+1/x)² - 2
⇒ ( x+1/x)² = 29
∴ x + 1/x = √29
- x² + 1/x² = (x-1/x)² + 2·x·1/x [a²+b² = (a-b)² + 2 ab]
⇒ 27 = (x-1/x)² + 2
⇒ (x-1/x )² = 25
∴ x - 1/x = ±5.
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