Question

If x2+1/x2 =29.then find the value of x3-y3

Answer 1

Answer:117

Step-by-step explanation:

x^2+y^2=29 and xy=10

so..

x^2 + y^2 = 29

or (x - y)^2 + 2xy = 29

or (x - y)^2 + 2 × 10 = 29

or (x - y)^2 = 9

or (x - y) = 3

so x-y = 3

hence the value of x^3 - y^3 will be ----

x^3 - y^3

= (x - y)^3 + 3xy(x - y)

= 3^3 + 3 × 10 × 3

= 27 + 90

= 117

Mark the answer as brainliest....