Math, asked by anjujaiswal2020, 4 days ago

if x² + 1/x² = 62 , find the value of x - 1/x​

Answers

Answered by dayanidhisharma19
1

Answer:

The value of x - 1/x is = √60

Step-by-step explanation:

It is given that,

x^2+ 1/x^2 =62,

Now we have to find the value of x-1/x,

Now we know, that,

(x - 1/x) ^2 = x^2 +(1/x) ^2 - 2×x×(1/x)

= x^2 + 1/x^2 - 2× 1

= x^2 + 1/x^2 -2

Now putting the value of x^2 + 1/x^2, we get,

(x - 1/x) ^2 = 62 - 2 = 60

=> (x - 1/x) = √60

THEREFORE, the value of x - 1/x = √60

Answered by krishpmlak
0

Answer:

Step-by-step explanation:

Given that,

x² + 1/x² = 62

( x - 1/x )² = x²+ 1/x ² - 2 × x × 1/x

= 62 - 2

= 60

∴(x - 1/x )= √60 or 2√15 is the answer.

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