Question

If x2+1/x2=62 findx+1/x

Answer 1

Answer:

x + 1/x = 8.

Correct question:

If x2 + 1/x2 = 62 then find the value of (x + 1/x).

Answer:

x + 1/x = 8.

Step-by-step explanation:

x²+1/x² = 62

• Upin adding 2 both sides

(x² +1/x² )+2 = 62 +2

• as we know (x+1/x)² = x²+1/x²+2

(x+1/x)² = 64

• taking roots on both sides

x+1/x = 8

In Mathematics, factorisation or factoring is defined as the breaking or decomposition of an entity (for example a number, a matrix, or a polynomial) into a product of another entity, or factors which when multiplied together give the original number or a matrix, etc.

A “quadratic” is a polynomial that is written like “ax2 + bx + c”, where “a”, “b”, and “c” are just numbers.

For an easy case of factoring, you can identify the two numbers that will not only multiply to equal the constant term “c” but also add up to equal “b,” the coefficient on the x-term.

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Answer 2

The value of  $x+\frac{1}{x}$ is 8.

Step-by-step explanation:

Given:

$x^{2} +\frac{1}{x^{2} }=62$.

To Find:

The value of  $x+\frac{1}{x}$.

Formula Used:

$(p+q)^{2} = p^{2} +q^{2} +2pq$  ---- formula no.01.

Solution:

As given,$x^{2} +\frac{1}{x^{2} }=62$.

Applying the formula no.01.

$(x+\frac{1}{x} )^{2} =x^{2} +\frac{1}{x^{2} } +2\times x\times \frac{1}{x}$

$(x+\frac{1}{x} )^{2} =x^{2} +\frac{1}{x^{2} } +2$

$(x+\frac{1}{x} )^{2} =62 +2$

$(x+\frac{1}{x} )^{2} =64$

$(x+\frac{1}{x} ) =\sqrt{64}$

$x+\frac{1}{x} =8$

Thus,the value of  $x+\frac{1}{x}$ is 8.

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