If x² + 1/x²= 66, find the value of x - 1/x
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Given : x² + 1/x² = 66
We know that, (x - 1/x)² = x² + (1/x)² - 2 × x × 1/x
[By using identity , (a - b)² = a² + b² - 2ab]
(x - 1/x)² = x² + (1/x)² - 2
(x - 1/x)² =66 - 2
(x - 1/x)² = 64
(x - 1/x) = ±√64
[Taking square root on both sides]
x - 1/x = ±8
Hence the value of x - 1/x is ±8.
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