Math, asked by WeirdAN, 1 month ago

if x²+1/x²=66,find the value of x³+1/x³​

Answers

Answered by rkcomp31
1

Answer:

Step-by-step explanation:

x²+1/x²=66

x²+1/x²+2*x*1/x=66+2

(x+1/x)²=68

x+1/x=2√17

(x²+1/x²)(x+1/x)=66*2√17

x³+x²/x+x/x²+1/x³=132√17

x³+1/x³+x+1/x=132√17

x³+1/x³=132√17-(x+1/x)

=132√17-2√17

=130√17

Thus x³+1/x³=130√17

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