if x2+1/x2 =7.find the value of i x+1/x ii x-1/x iii 2x2-2/2x2
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x^2 + 1/x^2 = 7
we know (x + 1/x)^2 = x^2 + 1/x^2 + 2
So, (x +1/x)^2 = 7+2=9
so, x + 1/x = 3
also,
(x - 1/x)^2= x^2 + 1/x^2 -2
so, (x - 1/x)^2= 7-2 =5
so, (x - 1/x)= square toot of 5 = 2.236
we know (x + 1/x)^2 = x^2 + 1/x^2 + 2
So, (x +1/x)^2 = 7+2=9
so, x + 1/x = 3
also,
(x - 1/x)^2= x^2 + 1/x^2 -2
so, (x - 1/x)^2= 7-2 =5
so, (x - 1/x)= square toot of 5 = 2.236
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