if x²+1/x²=7 find the value of x³+1/x³
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x^2+1/x^2=7
(x+1/x)^2=7+2
(x+1/x)^2=9
x+1/x=3
(x+1/x)^3=x^3+3(x)^2 (1/x)+3 (x)(1/x)^2+1/x^3
3^3=x^3+3x+3/x+1/x^3
27=x^3+1/x^3+3 (x+1/x)
27=x^3+1/x^3+3×3
x^3+1/x^3=27-9
x^3+1/x^3=18
so your answer is 18
(x+1/x)^2=7+2
(x+1/x)^2=9
x+1/x=3
(x+1/x)^3=x^3+3(x)^2 (1/x)+3 (x)(1/x)^2+1/x^3
3^3=x^3+3x+3/x+1/x^3
27=x^3+1/x^3+3 (x+1/x)
27=x^3+1/x^3+3×3
x^3+1/x^3=27-9
x^3+1/x^3=18
so your answer is 18
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