If x2+1\x2 = 83, find the value of x3+1/x3.
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we will use the identity of (x-1/x)2=x2+1/x2 -2
=>(x+1/x)2= 83-2
=81
=>x+1/x=9
now x3+1/x3=(x+1/x)(x2+1/x2-1)
=9(83-1)
=9*82
=738
=>(x+1/x)2= 83-2
=81
=>x+1/x=9
now x3+1/x3=(x+1/x)(x2+1/x2-1)
=9(83-1)
=9*82
=738
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