if x²+1/x² find the vslue of x³+1/x³
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Answered by
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Hi friend,
Your question might be as follows
if x²+1/x²=7 find the value of x³+1/x³
→ x² + 1/x² = 7
→ x² + 1/x² - 2(x)(1/x) + 2(x)(1/x) = 7
→ (x+1/x)² -2 = 7
→ (x+1/x)² = 9
→ (x+1/x) = √9
→ (x+1/x) = 3
We need to find (x³+1/x³)
→ (x+1/x)³ = x³+1/x³ + 3(x)(1/x) {x+1/x}
→ x³+1/x³ = (x+1/x)³ - 3{x+1/x)
→ x³+1/x³ = 3³ - 3(3)
→ x³+1/x³ = 27-9
→ x³+1/x³ = 18
Hope it helps
Your question might be as follows
if x²+1/x²=7 find the value of x³+1/x³
→ x² + 1/x² = 7
→ x² + 1/x² - 2(x)(1/x) + 2(x)(1/x) = 7
→ (x+1/x)² -2 = 7
→ (x+1/x)² = 9
→ (x+1/x) = √9
→ (x+1/x) = 3
We need to find (x³+1/x³)
→ (x+1/x)³ = x³+1/x³ + 3(x)(1/x) {x+1/x}
→ x³+1/x³ = (x+1/x)³ - 3{x+1/x)
→ x³+1/x³ = 3³ - 3(3)
→ x³+1/x³ = 27-9
→ x³+1/x³ = 18
Hope it helps
Answered by
1
i hope this solution would help you.
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