Question

if x²+1/x² find the vslue of x³+1/x³

Answer 1

Hi friend,

Your question might be as follows

if x²+1/x²=7 find the value of x³+1/x³

→ x² + 1/x² = 7

→ x² + 1/x² - 2(x)(1/x) + 2(x)(1/x) = 7

→ (x+1/x)² -2 = 7

→ (x+1/x)² = 9

→ (x+1/x) = √9

→ (x+1/x) = 3

We need to find (x³+1/x³)

→ (x+1/x)³ = x³+1/x³ + 3(x)(1/x) {x+1/x}

→ x³+1/x³ = (x+1/x)³ - 3{x+1/x)

→ x³+1/x³ = 3³ - 3(3)

→ x³+1/x³ = 27-9

→ x³+1/x³ = 18

Hope it helps

Answer 2

i hope this solution would help you.