Question

if x²+1/x² x=3-2√2/3+2√2​

Answer 1

Step-by-step explanation:

if x²+1/x² x=3-2√2/3+2√2

x=(3-2√2/3+2√2)(3-2√2/3-2√2)

=(3-2√2)^2/(3^2-(2√2)^2)

=(3^2+(2√2)^2-2*3*2√2)/(9-8)

=(9+8-12√2)/1

=17-12√2

1/x=3+2√2/3-2√2

=(3+2√2/3-2√2)(3+2√2/3+2√2)

=(3+2√2)^2/(3^2-(2√2)^2)

=(3^2+(2√2)^2+2*3*2√2)/(9-8)

=(9+8+12√2)/1

=17+12√2

x+1/x=17-12√2+17+12√2=34

(x+1/x)^2 = 34^2

x^2 + 1/x^2 +2*x*1/x=1156

x^2 + 1/x^2 +2=1156

x^2 + 1/x^2 =1156-2

x^2 + 1/x^2 =1154