If x2−11x+30=(x+m)(x+n)
Determine the value of m and n?
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Answer:
Step-by-step explanation:
x²−11x+30=(x+m)(x+n)
x²−11x+30
x²-5x-6x-30
=x(x-5)-6(x-5)
=(x-5)(x-6)=(x+m)(x+n)
So m = -5 n = -6
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