Question

If x2 + 12x + k= is a perfect square, then the possible value of ‘k ’ is

Answer 1

Answer:

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Step-by-step explanation:

$let \: x {}^{2} + 12x + k = (ax + b)^{2} \\ = (x) {}^{2} + 2 \times 6 \times x + (y) {}^{2} (k = y {}^{2} ) \\ = x {}^{2} + 2 \times 6 \times x + (6) {}^{2} \\ = (x + 6) {}^{2} \\ we \: had \: taken \: k = y {}^{2} \\ y = 6 = > y {}^{2} = 36 \\ k = 36$

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