Question

if x2 - 16x - 59 = 0, then what is the value of (x - 6)2 + [1/(x - 6)2]?
(a) 14 (b) 18 (c) 16 (d) 20
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Answer 1

Answer: pls mark my anser brainlist

Let y=x−6⟹x=y+6

x2−16x−59=0⟹(y+6)2−16(y+6)−59=0

⟹y2+12y+36−16y−96−59=0

⟹y2−4y−119=0

⟹x−6=y=1±123−−−√=13.09054 OR −9.09054

P=(x−6)2+1(x−6)2=y2+1y2

Substituting both the values, P=171.368 OR 82.64995

Little clumsy answer!