Question

if x2+1x2=47, then find the value of x3+1x3.​

Answer 1

Answer:

²+1/x² =47

Add 2(x*1/x) on sides,

x²+1/x²+2=47+2

(x+1/x)² =49

(x+1/x) =√49

x+1/x =7

Then, cube on both sides,

(x+1/x)³=7³

x³+1/x³+3(x*1/x){x+1/x} =343

x³+1/x³+3{7}=343

x³+1/x³+21=343

x³+1/x³=343-21

x³+1/x³=322

I hope this much will help you