Question

If x2 + 25y2 = 274 and y=21x, then what is the value of (x 5y)2

Answer 1

Step-by-step explanation:

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Answer 2

The value of  $(x-5y)^2$ $=274-210x^{2}$

Step-by-step explanation:

We have,

$x^2$ + 25$y^2$ = 274 and y = 21x

To find, the value of  $(x-5y)^2=?$

Using the algebraic identity,

$(a-b)^{2}=a^{2}+b^{2}-2ab$

∴ $(x-5y)^2$

$=x^2 + 25y^2-10xy$

Put $x^2$ + 25$y^2$ = 274 and y = 21x, we get

$=274-10x(21x)$

$=274-210x^{2}$

∴ The value of  $(x-5y)^2$ $=274-210x^{2}$