Question

If x2 -2x+1=0then x+1\x is equal

Answer 1

$Given \: Quadratic \: Equation :\\ x^{2} - 2x + 1 =0$

$\implies x^{2} - 2 \times x \times 1 + 1^{2} = 0$

$\implies ( x - 1 )^{2} = 0$

$\implies x - 1 = 0$

$\implies \green {x = 1}$

$Now, \: Value \: of \: x + \frac{1}{x} \\= \green {1} + \frac{1}{\green {1}} \\= 1 + 1 \\= 2$

Therefore.,

$\red{Value \: of \: x + \frac{1}{x}} \green {= 2 }$

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