If x² + 2x + k is completely divisible by x - 1 , find the value of 'k'.
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2
remainder should be 0.
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mysticd:
there is no need of doing divison
use remainder theorem
yup.. apna apna choice hai..
Answered by
5
(x - 1) is completely divisible means
( x -1) is a factor of x² + 2x + K ,
hence, x = 1 is a zeros of x² + 2x + K
so, if we put x = 1 then x² +2x + K must be zero .
so, ( 1)² + 2( 1) + K =0
1 + 2 + K = 0
K = -3
( x -1) is a factor of x² + 2x + K ,
hence, x = 1 is a zeros of x² + 2x + K
so, if we put x = 1 then x² +2x + K must be zero .
so, ( 1)² + 2( 1) + K =0
1 + 2 + K = 0
K = -3
Dude which class???
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