if x2=3,then find quadratic equation
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Answer:
If x=
3
2
,x=−3 are roots of the equation ax
2
+7x+b=0 then
(x−
3
2
)(x−(−3))=0
⇒(x−
3
2
)(x+3)=0
⇒x
2
−
3
2
x+3x−2=0
⇒x
2
+
3
7
x−2=0
⇒3x²+7x−6=0
Compare the equation with ax²+7x+b=0
Therefore, a=3,b=−6
Step-by-step explanation:
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