if x²-3x+2 divides x³-6x²+ax+b exactly,then find the value of a and b.
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Answer:
11, -6
Step-by-step explanation:
x²-3x+2 has two roots 1,2
as x²-3x+2 divides x³-6x²+ax+b ,1 and 2 are also roots of x³-6x²+ax+b
substitute 1 in x³-6x²+ax+b
==> 1-6+a+b=0
==>a+b=5 (1)
substitute 2 in x³-6x²+ax+b
====>8-24+2a+b=0
===>2a+b=16 (2)
solving 1,2
a=11,b=-6
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