if x²-3x+2 is a factor of x4-ax²+b find a, b .hence factorise completely...
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7
x^2 - 3x + 2 = (x - 2)(x - 1)
x = 1, x = 2 make f(x) zero :
x = 1,
1^4 - a(1)^3 + b = 0
a - b = 1
x = 2,
2^4 - a(2)^3 + b = 0
16 - 8a + b = 0
-8a + b = -16
=>
a - b = 1
-8a + b = -16
a = 15/7, b = 8/7
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refer to the attachment....
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