Question

If x²+4x-1=0 and x is positive then find the value of x+1/x

Answer 1

I think in question x² + 4x - 1 = 0 is wrong
the correct equation is x² + 4x + 1 = 0

${x}^{2} + 4x + 1 = 0 \\ {x}^{2} + 4x = - 1 \\ x(x + 4) = - 1 \\ x = \frac{ - 1}{x + 4} \\ \\ x + \frac{1}{x} = \frac{ - 1}{x + 4} + \frac{1}{ \frac{ - 1}{x + 4} } \\ x + \frac{1}{x} = - 1( \frac{1}{x + 4} + (x + 4)) \\ x + \frac{1}{x} = - 1 (\frac{ 1 + (x + 4)(x + 4)}{(x + 4)} \\ x + \frac{1}{x} = - 1( \frac{1 + {x}^{2} + 8x + 16 }{x + 4}) \\ x + \frac{1}{x} = - 1( \frac{ {x}^{2} + 8x + 17 }{x + 4} ) \\ x + \frac{1}{x} = - 1( \frac{( {x}^{2} + 4x + 1) + 4x + 16}{x + 4}) \\ x + \frac{1}{x} = - 1( \frac{(0) + 4x + 16}{x + 4} ) \\ x + \frac{1}{x} = - 1(\frac{4(x + 4)}{x + 4} ) \\ x + \frac{1}{x} = - 4$
#mark as brainliest

Answer 2

I hope this will help u