Question

if X2+4x+10/2x+5=X2+8x+20/4x+10 then x=?​

Answer 1

Answer:

this is right answer

Step-by-step explanation:

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Answer 2

Given :- if x² + 4x + 10 / 2x + 5 = x² + 8x + 20 / 4x + 10 , find x = ?

Solution :-

→ (x² + 4x + 10) / (2x + 5) = (x² + 8x + 20) / (4x + 10)

taking 2 common from RHS denominator,

→ (x² + 4x + 10) / (2x + 5) = (x² + 8x + 20) / 2(2x + 5)

(2x + 5) will be cancel from both sides denominator,

→ 2(x² + 4x + 10) = x² + 8x + 20

→ 2x² + 8x + 20 = x² + 8x + 20

→ 2x² - x² + 8x - 8x + 20 - 20 = 0

→ x² = 0

→ x = 0 .

now, again,

→ (x² + 4x + 10) / (2x + 5) = (x² + 8x + 20) / (4x + 10)

multiply by (1/2) both sides ,

→ (x² + 4x + 10) / (4x + 10) = (x² + 8x + 20) / (8x + 20)

using divindo now, we get,

→ [(x² + 4x + 10) - (4x + 10)] / (4x + 10) = [(x² + 8x + 20) - (8x + 20)] / (8x + 20)

→ x²/(4x + 10) = x²/(8x + 20)

x² will be cancel from both sides,

→ 1/(4x + 10) = 1/(8x + 20)

→ 4x + 10 = 8x + 20

→ 8x - 4x = 10 - 20

→ 4x = (-10)

→ x = (-2.5) .

Hence, value of x will be (-2.5 and 0.)

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if a^2+ab+b^2=25

b^2+bc+c^2=49

c^2+ca+a^2=64

Then, find the value of

(a+b+c)² - 100 = ...

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