Question

if x² - 4x + 5 - sin y =0, y belongs to [0,2pi], then​

Answer 1

Answer:

Step-by-step explanation:siny=x^2-4x+5

y belongs to (0,2pi) so siny goes from -1 to +1

So -1<=x^2-4x+5

0<=x^2-4x+6

And

x^2-4x+5<=1