Question

if x²-4x+p=0 has real roots,then
p>or=4
p<or=4
p>or=5​

Answer 1

Answer:

$p \geqslant 4$

step by step :

D=b^2 -4ac

D=(-4)^2-4×1×p

D=16-4p

4p>or=16

So p> or=4

pls mark my answer as brainliest