Question

If x2+4y2−8x+12=0 is satisfied by real values of x and y then x lies between

Answer 1

Answer:

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Step-by-step explanation:

If x2 + 4y2 - 8x + 12 = 0 is satisfied by real values of x and y t. Prove that if the equation x2+9y2-4x+3=0 is satisfied for real values of xandy,thenx must lie between 1 and 3 andy must lie between-1/3 and 1/3