Question

if x² 5bx 16=0 has no real roots, then:​

Answer 1

Answer:

Given equation x2 + 5kx + 16 = 0 Comparing it by general quadratic equation ax2 + bx + c = 0 a = 1, b = 5k, c = 16 Discriminant (D) = b2 – 4ac = (5k)2 – 4 × 1 × 16 = 25k2 – 64 If Discriminant (D) < 0, then roots will not be real. i.e. D < 0 ⇒ 25k2 – 64 < 0 ⇒ (5k – 8)(5k + 8) < 0 ⇒ 5k – 8 < 0 or 5k + 8 < 0 ⇒ k < 8/5 or k > -8/5 Hence, value of k will be smaller than 8/5 or greater than -8/5Read more on Sarthaks.com - https://www.sarthaks.com/748437/find-value-of-k-for-which-equation-x-2-5kx-16-0-has-no-real-roots.

Step-by-step explanation:

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