If x2 + 5px + 16 has no real roots, then
Answers
Answered by
0
Answer:
The given quadratic equation is x 2 + 5px + 16 = 0 ........(1)
Comparing it with ax 2 + bx + c = 0, we get a = 1, b = 5p, c = 16
If equation (1) has no real roots, then discriminant ( D ) < 0
⇒ b 2 - 4ac < 0 ⇒ (5p) 2 - 4 × (1) × (16) < 0
⇒ 25p 2 - 64 < 0 ⇒ 25p 2 < 64
⇒ p 2 <
64
25
⇒ p 2 -
64
< 0
25
⇒ p -
8
p +
8
< 0
5 5
⇒ either p -
8
> 0 and p +
8
< 0
5
5
⇒ p >
8
and p < -
8
,
5
5
Which is not Possible
⇒ p -
8
> 0 and p +
8
< 0
5
5
⇒ p <
8
and p > -
8
, ⇒ -
8
< p <
8
.
5
5
5
5
Therefore , required answer will be option B .
Answered by
0
Answer:
If X2 + 5px + 16 has no real roots, then the discriminant < 0 .
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