Question

If (x2-5x+6)2+(x2-7x+12)2=0 then the value if x is

Answer 1

( x^2 - 5x + 6 ) × 2 + ( x^2 - 7x + 12 ) × 2 = 0

( 2x^2 - 10x + 12 ) + ( 2x^2 - 14x + 24 ) = 0

2x^2 + 2x^2 - 10x - 14x + 12 + 24 = 0

4x^2 - 24x + 36 = 0

4x × x - 24x + 36 = 0

-20x × x + 36 = 0

x × x = 0 - 36 / - 20

x × x = 36 / 20

x =

$\sqrt{36 \div 20}$
x = 6 / 4.47


therefore answer is 6 / 4.47