Question

If x2 = 64 and x > 0, find the value of  x13+x0​

Answer 1

Step-by-step explanation:

• Given If x^-2 = 64 and x > 0, find the value of  x^1/3 + x^0  
• Now given x^-2 = 64
• We can write this as  x^-2 = 2^6
•  Or 1/x^2 = 1 / 2^-6
•    Or x^2 = 2^-6
•    So x^2 = 1 / 64
•    Or x = 1/8  
• Now we get x = 1/8 , substituting this we get
•                So x^1/3 + x^0  
•                So (1/8)^1/3 + 1  
•               (1/2^3)^1/3 + 1
•                1 / (2^3)^1/3 + 1
•               1/2 + 1
•                   = 3/2

Reference link will be

https://brainly.in/question/9660559