If,x2 = .64, then value of xº + x3 is equal to
Answers
Answered by
0
Answer:
Explanation:
x
−
2
=
64
⇒
1
x
2
=
64
⇒
x
2
=
1
64
⇒
x
=
±
1
8
.
⇒
1
x
=
±
8
.
∴
1
x
3
+
x
0
=
(
1
x
)
3
+
1
=
(
±
8
)
3
+
1
=
±
512
+
1
.
∴
The Reqd. Value=
513
,
or
−
511
.
Answer link
Jumbotron
Jan 27, 2018
Please see another method in resolving below;
Explanation:
Given;
x
−
2
=
64
Using Indices
Recall:
x
−
1
=
1
x
x
−
2
=
64
1
x
2
=
64
1
x
2
=
64
1
Cross multiplying..
64
×
x
2
=
1
×
1
64
⋅
x
2
=
1
Divide both sides by
64
64
⋅
x
2
64
=
1
64
64
⋅
x
2
64
=
1
64
x
2
=
1
64
Squareroot both sides..
√
x
2
=
√
1
64
x
=
1
8
Hence;
1
x
3
+
x
0
1
(
1
8
)
3
+
(
1
8
)
0
Recall:
x
0
=
1
1
(
1
8
)
3
+
1
1
1
512
+
1
1
÷
1
512
+
1
1
×
512
1
+
1
×
×
x
512
1
→
Transposed
1
×
512
+
1
512
+
1
513
→
Answer
Hope this helps and its well understood!
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