Question

If x² + 6x - 27 > 0 and x² - 3x - 4 <0 then find the solution.​

Answer 1

Answer:

x

2

+6x−27>0

x

2

+9x−3x−27>0

x(x+9)−3(x+9)>0

(x−3)(x+9)>0

x∈(−∞,−9)∪(3,∞)

x

2

−3x−4<0

x

2

−4x+x−4<0

x(x−4)+(x−4)<0

(x+1)(x−4)<0

x∈(−1,4)

∴x∈(3,4)

or,3<x<4