if X2+6x+k=(x+3)2,then what is K equal to
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Step-by-step explanation:
A quadratic equation ax^2+bx+c=0ax
2
+bx+c=0 has equal roots if
b^2-4ac=0b
2
−4ac=0 ...(1)
The given equation is
x^2+6x+k=0x
2
+6x+k=0
Here, a=1, b=6 and c=k. Substitute these values in equation (1).
(6)^2-4(1)(k)=0(6)
2
−4(1)(k)=0
36-4k=036−4k=0
Subtract 36 from both sides.
-4k=-36−4k=−36
Divide both sides by -4.
k=9k=9
Therefore, the value of k is 9.
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