Question

If (x2 – 7x + 10) (y2 + y + 1) < 2y for all real y then x belongs to the interval (3, b) then b can be​

Answer 1

Answer:

each edge of the cube is increased by 50. find then increase in area of the cube

Step-by-step explanation:

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Answer 2

Answer:

Required value of b can be greater than (-1).

Step-by-step explanation:

Given,

$( {x}^{2} - 7x + 10)( {y}^{2} + y + 1) < 2y$

It is also given that x and y belongs to (3,b).

We want to find value of b.

So,we are putting x = 3 and y = b in given equation.

$( {3}^{2} - 7 \times 3 + 10)( {b}^{2} + b + 1) < 2b \\ (9 - 21 + 10)( {b}^{2} + b + 1) < 2b \\ - 2 \times ( {b}^{2} + b + 1) < 2b \\ - {b}^{2} - b - 1 < b \\ - {b}^{2} - 2b - 1 < 0 \\ {b}^{2} + 2b + 1 > 0 \\ {(b + 1)}^{2} > 0 \\ b + 1 > 0 \\ b > - 1$

So, b can be greater than (-1).

This is a problem of equation part of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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