Question

If x²-8x-15=0 and (x-2)(x-p)=0 and one root is common then 'p' is...
Plz answer the question...​

Answer 1

Answer:

$x²-8x + 15=0$

$p \: is \: 1 \: root$

So

${p}^{2} - 8p + 15 = 0$

$(p - 3)(p - 5) = 0$

p=3,5

$(x-2)(x-p)=0$

x=2,p

so p=3 or 5.

Answer 2

Answer:

this question is printing mistake instead of -15 it should be +15 . and it's answer should be 3 or 5. but in given equation there are no roots are common