Question

If x2+ax+10=0 and x2+bx-10=0 has one root common then

Answer 1

Answer:

Step-by-step explanation:

Let m is the common root of

x2+ax+10=0 and x2+bx-10=0

then

m2+ma+10=0=m2+bm-10-----(1)

m(a-b)=-20

m=20/a-b

putting value of m in (1)

[20/(a-b]²+a*20/a-b+10=0

20+20a(a-b)+10(a-b)²=0

2+2a²-2ab+a²+b²-2ab=0

3a²-3ab+b²+2=0