Question

If x²-ax+36=(x-4)(x-9) then A is equal to

Answer 1

The value of a = 13

Given :

$\displaystyle \sf{ {x}^{2} - ax + 36 = (x - 4)(x - 9) }$

To find :

The value of a

Solution :

Step 1 of 2 :

Write down the given equation

The given equation is

$\displaystyle \sf{ {x}^{2} - ax + 36 = (x - 4)(x - 9) }$

Step 2 of 2 :

Find the value of a

$\displaystyle \sf{ {x}^{2} - ax + 36 = (x - 4)(x - 9) }$

$\displaystyle \sf{ \implies {x}^{2} - ax + 36 =x(x - 9) - 4(x - 9) }$

$\displaystyle \sf{ \implies {x}^{2} - ax + 36 = {x}^{2} - 9x - 4x + 36 }$

$\displaystyle \sf{ \implies {x}^{2} - ax + 36 = {x}^{2} - 13x + 36 }$

Comparing both sides we get a = 13

Hence the required value of a = 13

Answer 2

Given:

x²-ax+36=(x-4)(x-9)

To find:

The value of a

Solution:

The value of a is 13.

We can find the value by following the given process-

We know that the value can be obtained by expanding the brackets.

We are given the following-

x²-ax+36=(x-4)(x-9)

We will solve the given equation to get the value of a.

On solving, we get

x²-ax+36=x(x-9)-4(x-9)

x²-ax+36=$x^{2}$-9x-4x+36

-ax= -13x

ax= 13x

a=13

Therefore, the value of a is 13.