Math, asked by ammutty42, 8 months ago

If x2+ax+b is a perfect square prove that a2=4b.​

Answers

Answered by sklaiba137
4

Step-by-step explanation:

x2+ax+b

=(x)2+2(a2)x+(b√)2

Now, above quadratic polynomial will be a perfect square only if the coefficient of x is ±2 times the square root of product of coefficient of x2 & constant as follows

a=±21⋅b−−−√

a=±2b√

a2=(±2b√)2

a2=4b

Answered by acsahjosemon40
0

Answer:

x2+ax+b

=(x)2+2(a2)x+(b√)2

Now, above quadratic polynomial will be a perfect square only if the coefficient of x is ±2 times the square root of product of coefficient of x2 & constant as follows

a=±21⋅b−−−√

a=±2b√

a2=(±2b√)2

a2=4b

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