If x2+ax+b is a perfect square prove that a2=4b.
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Answered by
4
Step-by-step explanation:
x2+ax+b
=(x)2+2(a2)x+(b√)2
Now, above quadratic polynomial will be a perfect square only if the coefficient of x is ±2 times the square root of product of coefficient of x2 & constant as follows
a=±21⋅b−−−√
a=±2b√
a2=(±2b√)2
a2=4b
Answered by
0
Answer:
x2+ax+b
=(x)2+2(a2)x+(b√)2
Now, above quadratic polynomial will be a perfect square only if the coefficient of x is ±2 times the square root of product of coefficient of x2 & constant as follows
a=±21⋅b−−−√
a=±2b√
a2=(±2b√)2
a2=4b
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