Question

If x2+ax+b is a perfect square prove that a2=4b.​

Answer 1

Answer:

Method 1: Let perfect square be as follows

x2+ax+b=(x+k)2x2+ax+b=(x+k)2

x2+ax+b=x2+2kx+k2x2+ax+b=x2+2kx+k2

Comparing the corresponding coefficients on both the sides, we get

a=2k, b=k2a=2k, b=k2

⟹b=(a2)2⟹b=(a2)2

b=a24b=a24

a2=4b

Step-by-step explanation:

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