Question

if x²+ax+b leaves the same remainder when divided either by x+1,find the value of a and b​

Answer 1

Answer:

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Answer:

$a = 0 ; b = 4$

Step-by-step explanation:

let , p(x) = x²+ax+b

given, p(x) / (x-1 ) leaves remainder 5

⇒ p(1) = 5

⇒ 1²+a(1)+b = 5

⇒a+b = 5-1

⇒a+b=4 -------------- I

also p(x) / (x+1) leaves the same remainder 5.

⇒ p(-1) = 5

⇒ (-1)²+a(-1)+b = 5

⇒ 1 - a + b =5

⇒ -a+b = 5-1 = 4

ie., -a+b = 4 ------------------ II

add I and II ,

a + b -a + b = 4 + 4

2b = 8 ⇒ b=4

substitute b=4 in I , we get,

a + 4 = 4  ⇒ a = 4-4 =0

⇒ a = 0

Answer 2

Answer:

oh the Answer is a zero 0 I am right

Step-by-step explanation:

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