Question

if x²+ax+b=(X+2) (x-2) . find the value of a and b​

Answer 1

Answer:

The value of $a=0$ and $b=-4$.

Step-by-step explanation:

We have

$(x+2)(x-2)=x^{2}-2^{2}$

                      $=x^{2} -4$.

So, $x^{2} +ax+b=x^{2} -4$

equating with corresponding coefficients, we get

$a=0$ (since there is no terms containing x in $x^{2} -4$)

$b=-4$ (the constant part)

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