If x2+ ax+b, x² + cx + d have common factor (x - 1), then a +b-c-d is
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2
Step-by-step explanation:
Given (x−2) is a common factor of x
2
+ax+b and x
2
+cx+d
∴x=2 is a root of x
2
+ax+b=0 and x
2
+cx+d=0
∴4+2a+b=0,4+2c+d=0
⇒2a+b=2c+d
⇒2(c−a)=b−d
⇒
c−a
b−d
=2
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