if x² +ax²-bx-13 has × as factors
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210 is the coreect answer
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a=12 and b=0 is the correct answer plz mark me as brilianist
Step-by-step explanation:
p(x)=x-1
x-1=0
x=1
p(1)=(1)²+a(1)²-b(1)-13
=1+a-b-13
a-b-12
a-b=12__equation no.1
taking fron equation no.1,we get
a=12-b___equation no.2
substitutig the value of a=12-b in equation_no.1,
(12-b)-b=12
12-2b=12
-2b=12-12
b=0/2
b=0
substituting the value of b=0 in equation_no.2
a=12-(0)
a=12
answer:-a=12 and b=0
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