Question

if x2+(c-2)x-c2-3c+5 is divided by x+c, the remainder is -1. fond the value of c

Answer 1

Answer:

Blah blah blah blah mark as brainl-- plss

Answer 2

Step-by-step explanation:

f (x) = x2+ (c–2)x – c2 – 3c + 5 is divided by x + c the remainder is –1

f (x) = x2+ (c–2)x – c2 – 3c + 5 is divided by x + c the remainder is –1 f (–c) = (-c2)+(c-2)(-c)-c2-3c+5= -1

f (x) = x2+ (c–2)x – c2 – 3c + 5 is divided by x + c the remainder is –1 f (–c) = (-c2)+(c-2)(-c)-c2-3c+5= -1 =-c2+c2-2c-c2-3c+5= -1

f (x) = x2+ (c–2)x – c2 – 3c + 5 is divided by x + c the remainder is –1 f (–c) = (-c2)+(c-2)(-c)-c2-3c+5= -1 =-c2+c2-2c-c2-3c+5= -1 =-c2-5c+5= -1

f (x) = x2+ (c–2)x – c2 – 3c + 5 is divided by x + c the remainder is –1 f (–c) = (-c2)+(c-2)(-c)-c2-3c+5= -1 =-c2+c2-2c-c2-3c+5= -1 =-c2-5c+5= -1 = -c2-5c+6=0

f (x) = x2+ (c–2)x – c2 – 3c + 5 is divided by x + c the remainder is –1 f (–c) = (-c2)+(c-2)(-c)-c2-3c+5= -1 =-c2+c2-2c-c2-3c+5= -1 =-c2-5c+5= -1 = -c2-5c+6=0 =(c+3) (c-2)=0

f (x) = x2+ (c–2)x – c2 – 3c + 5 is divided by x + c the remainder is –1 f (–c) = (-c2)+(c-2)(-c)-c2-3c+5= -1 =-c2+c2-2c-c2-3c+5= -1 =-c2-5c+5= -1 = -c2-5c+6=0 =(c+3) (c-2)=0 c= -3 or c=2

f (x) = x2+ (c–2)x – c2 – 3c + 5 is divided by x + c the remainder is –1 f (–c) = (-c2)+(c-2)(-c)-c2-3c+5= -1 =-c2+c2-2c-c2-3c+5= -1 =-c2-5c+5= -1 = -c2-5c+6=0 =(c+3) (c-2)=0 c= -3 or c=2

I HOPE HELP YOU