if x2+(c-2)x-c2-3c+5 is divided by x+c, the remainder is -1. fond the value of c
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Step-by-step explanation:
f (x) = x2+ (c–2)x – c2 – 3c + 5 is divided by x + c the remainder is –1
f (x) = x2+ (c–2)x – c2 – 3c + 5 is divided by x + c the remainder is –1 f (–c) = (-c2)+(c-2)(-c)-c2-3c+5= -1
f (x) = x2+ (c–2)x – c2 – 3c + 5 is divided by x + c the remainder is –1 f (–c) = (-c2)+(c-2)(-c)-c2-3c+5= -1 =-c2+c2-2c-c2-3c+5= -1
f (x) = x2+ (c–2)x – c2 – 3c + 5 is divided by x + c the remainder is –1 f (–c) = (-c2)+(c-2)(-c)-c2-3c+5= -1 =-c2+c2-2c-c2-3c+5= -1 =-c2-5c+5= -1
f (x) = x2+ (c–2)x – c2 – 3c + 5 is divided by x + c the remainder is –1 f (–c) = (-c2)+(c-2)(-c)-c2-3c+5= -1 =-c2+c2-2c-c2-3c+5= -1 =-c2-5c+5= -1 = -c2-5c+6=0
f (x) = x2+ (c–2)x – c2 – 3c + 5 is divided by x + c the remainder is –1 f (–c) = (-c2)+(c-2)(-c)-c2-3c+5= -1 =-c2+c2-2c-c2-3c+5= -1 =-c2-5c+5= -1 = -c2-5c+6=0 =(c+3) (c-2)=0
f (x) = x2+ (c–2)x – c2 – 3c + 5 is divided by x + c the remainder is –1 f (–c) = (-c2)+(c-2)(-c)-c2-3c+5= -1 =-c2+c2-2c-c2-3c+5= -1 =-c2-5c+5= -1 = -c2-5c+6=0 =(c+3) (c-2)=0 c= -3 or c=2
f (x) = x2+ (c–2)x – c2 – 3c + 5 is divided by x + c the remainder is –1 f (–c) = (-c2)+(c-2)(-c)-c2-3c+5= -1 =-c2+c2-2c-c2-3c+5= -1 =-c2-5c+5= -1 = -c2-5c+6=0 =(c+3) (c-2)=0 c= -3 or c=2
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