Question

If x² + kx + 10 = (x - 2) ( x - 5) then find the value of k.​

Answer 1

Answer:

k = -8

Formula is :

Let p(x)=x

Let p(x)=x 3

Let p(x)=x 3 −3x

Let p(x)=x 3 −3x 2

Let p(x)=x 3 −3x 2 +kx−10

Let p(x)=x 3 −3x 2 +kx−10if (x−5), is a factor of p(x)

Let p(x)=x 3 −3x 2 +kx−10if (x−5), is a factor of p(x)then p(x)=0

Let p(x)=x 3 −3x 2 +kx−10if (x−5), is a factor of p(x)then p(x)=0(5)

Let p(x)=x 3 −3x 2 +kx−10if (x−5), is a factor of p(x)then p(x)=0(5) 3

Let p(x)=x 3 −3x 2 +kx−10if (x−5), is a factor of p(x)then p(x)=0(5) 3 −3(5)

Let p(x)=x 3 −3x 2 +kx−10if (x−5), is a factor of p(x)then p(x)=0(5) 3 −3(5) 2

Let p(x)=x 3 −3x 2 +kx−10if (x−5), is a factor of p(x)then p(x)=0(5) 3 −3(5) 2 +k(5)−10=0

Let p(x)=x 3 −3x 2 +kx−10if (x−5), is a factor of p(x)then p(x)=0(5) 3 −3(5) 2 +k(5)−10=0⇒125−75+5k−10=0

Let p(x)=x 3 −3x 2 +kx−10if (x−5), is a factor of p(x)then p(x)=0(5) 3 −3(5) 2 +k(5)−10=0⇒125−75+5k−10=0⇒40+5k=0

Let p(x)=x 3 −3x 2 +kx−10if (x−5), is a factor of p(x)then p(x)=0(5) 3 −3(5) 2 +k(5)−10=0⇒125−75+5k−10=0⇒40+5k=0⇒5k=−40

Let p(x)=x 3 −3x 2 +kx−10if (x−5), is a factor of p(x)then p(x)=0(5) 3 −3(5) 2 +k(5)−10=0⇒125−75+5k−10=0⇒40+5k=0⇒5k=−40⇒k=−8

Let p(x)=x 3 −3x 2 +kx−10if (x−5), is a factor of p(x)then p(x)=0(5) 3 −3(5) 2 +k(5)−10=0⇒125−75+5k−10=0⇒40+5k=0⇒5k=−40⇒k=−8Thus k=−8

Answer 2

Answer:

VALUE OF k= -7

Step-by-step explanation:

PLEASE REFER TO THE ATTACHMENT FOR DETAILED SOLUTION.

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