Question

If x²+kx-11=0 has real and distinct roots then the value of k can be?

Answer 1

Step-by-step explanation:

We have, the equation,

${x}^{2} + kx - 11 = 0$

For real and distinct roots,

its discriminant, D>0

${k}^{2} - 4 \times ( - 11) \times 1 > 0$

${k}^{2} + 44 > 0$

Which is always true,

So,

for all real values of k, the equation has real and distinct roots