Question

If x2 + kx + 6 = (x + 2)(x + 3) for all x, the value of k is

Answer 1

Answer:

x2+kx+6=(x+2)(x+3) for all values of x

To find the value of k

Sol: x2+kx+6=(x+2)(x+3)⟹x2+kx+6=x(x+3)+2(x+3)⟹x2+kx+6=x2+3x+2x+6⟹x2+kx+6=x2+5x+6

Equating both sides in the above condition we get, 

The value of k=5