If x²+kx + 6 = ( x+2) (x+3) for all x , then the value of k is
a) 1
b) -1
c) 5
d) 3
explain with ans .
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Given: x +kx+6=(x+2)(x+3) for all values of x
To find the value of k
Sol:
x +kx+6=(x+2)(x+3)
⟹x +kx+6=x(x+3)+2(x+3)
⟹x +kx+6=x +3x+2x+6
⟹x +kx+6=x +5x+6
Equating both sides in the above condition we get,
The value of k=5
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